A straight wire with a length of 0,20m move at a constant speed of 3,3m.s at right angle to a magnetic field of flux density 0,,15T..calculate the emf induced across the ends of the wire?
To calculate the induced electromotive force (emf) across the ends of the wire, you can use the formula:
emf = B * L * v * sin(θ)
Where:
- B is the magnetic field strength or flux density in Tesla (T)
- L is the length of the wire perpendicular to the magnetic field in meters (m)
- v is the velocity or speed of the wire in meters per second (m/s)
- θ is the angle between the velocity vector and the magnetic field (90 degrees, since the wire moves at a right angle to the magnetic field)
Given:
- B = 0.15 T
- L = 0.20 m
- v = 3.3 m/s
First, let's calculate sin(θ):
sin(90°) = 1
Now substitute the given values into the formula:
emf = 0.15 T * 0.20 m * 3.3 m/s * 1
Calculating the emf:
emf = 0.15 * 0.20 * 3.3 * 1
emf = 0.099 V
Therefore, the induced electromotive force across the ends of the wire is 0.099 V.