How do i do thois problem?Please help.
Problem #1
solve the system by subtraction.
5x-3y=13
4x-3y=11
Subtract the lower equation's left and right terms from the upper equation's corresponding terms. The first step will get you this:
x = 2
Now that you know x, use either of the two equations, and substitute of x=2, to solve for y.
To solve the system of equations by subtraction, follow these steps:
Step 1: Write down both equations:
5x - 3y = 13
4x - 3y = 11
Step 2: Choose one equation to eliminate one variable. In this case, let's eliminate the "y" variable. To do this, subtract the second equation from the first equation. Subtract the left side of the second equation (4x - 3y) from the left side of the first equation (5x - 3y), and subtract the right side of the second equation (11) from the right side of the first equation (13).
(5x - 3y) - (4x - 3y) = 13 - 11
x - 0 = 2
x = 2
After subtracting, you get the equation x = 2. This gives you the value of x.
Step 3: Substitute the value of x into either of the original equations to solve for y. Let's use the first equation:
5x - 3y = 13
5(2) - 3y = 13
10 - 3y = 13
-3y = 13 - 10
-3y = 3
y = 3/(-3)
y = -1
By substituting x = 2 back into the original equations, you find that y = -1.
So the solution to the system of equations is x = 2 and y = -1.