The xyz corporation claims that there's NO DIFFERENCE in the salary of female and male workers at the Southern California plant. A human rights agency took two samples(25 each) .the male sample gad a mean of 350per week wit standard deviation of 50. The female sample had a mean salary of 320 per week with standard deviation of 30. At alfa .02is there enough evidence to support the XYZ corporation claim? Test thus claim using both method.

Question

The xyz corporation claims that there's NO DIFFERENCE in the salary of female and male workers at the Southern California plant. A human rights agency took two samples(25 each) .the male sample gad a mean of 350per week wit standard deviation of 50. The female sample had a mean salary of 320 per week with standard deviation of 30. At alfa .02is there enough evidence to support the XYZ corporation claim? Test thus claim using both method.

Answer 1

Which methods?

Here is one.

Z = (mean1 - mean2)/standard error (SE) of difference between means

SEdiff = √(SEmean1^2 + SEmean2^2)

SEm = SD/√n

If only one SD is provided, you can use just that to determine SEdiff.

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability
related to the Z score.