Force of 2.25N is acting on charge 15x10^-4C at any point. Find the Electric Field Intensity at that point.

1500 N/C

To find the electric field intensity at a point due to a given force acting on a charge, we can use Coulomb's Law. Coulomb's Law states that the electric field intensity (E) at a point in space is equal to the force (F) acting on a charge (q) at that point, divided by the magnitude of the charge.

The formula for electric field intensity is given as:

E = F / q

Given:
Force, F = 2.25 N
Charge, q = 15 × 10^(-4) C

Substituting the values into the formula, we get:

E = 2.25 N / (15 × 10^(-4) C)

To simplify the calculation, we can express 15 × 10^(-4) as 1.5 × 10^(-3):

E = 2.25 N / (1.5 × 10^(-3) C)

Now, divide 2.25 N by 1.5 × 10^(-3) C to find the electric field intensity:

E = 2.25 N / 1.5 × 10^(-3) C

E ≈ 1500 N/C

Therefore, the electric field intensity at the given point is approximately 1500 N/C.