Precaculculus

Suppose you are told that log(2)=0.3562 and log(3)=0.5646. All of them with the base of 'a'. Find:
i) log(6)
ii) log(9)

Solutions

i) log(6)= log (3)(2)
= log 3 + log 2
= 0.5646 + 0.3562
= 0.9208

ii)log(9)= log 3^2
= 2 log 3
= 2 (0.5646)
= 1.1292

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  1. you are correct.

    An interesting question now would be ...
    what is the value of 'a' ?

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