trigonometry

1/sin2A+cos4A/sin4A

  1. 👍
  2. 👎
  3. 👁
  1. If you mean
    1/sin2x + cos4x/sin4x
    then that is
    1/sin2x + (2cos^2 2x - 1)/(2sin2x cos2x)

    = (2cos2x + 2cos^2 2x - 1)/(2sin2x cos 2x)

    Not sure just what you are after

    1. 👍
    2. 👎
  2. 1/sin2x+2(cos2x)^2 -1/2sin2xcos2x
    = 1/sin2x[2cos2x+2(cos2x)^2 - 1]/2cos2x
    =[2cos2x+2(cos2x)^2 -1]/sin4x

    1. 👍
    2. 👎

Respond to this Question

First Name

Your Response

Similar Questions

  1. Trig

    How do you express sin4x as a trigonometric funcition of x using the identities? I think that you are supposed to start with the sine sum identity and then use the double angle identities for sin2A and cos2A, but after that I get

  2. Trigonometry

    If sinA=3/5 and cosB=5/13 and if A and B are measures of two angles in Quadrant I, find the exact value of the following functions. cotB = sin2A= 3)cos(5pi/6 + B) = tan(A - pi/4) =

  3. Math

    If sinA=0.5 , what is the value of cos2A and sin2A?

  4. Grade 12 Trigonometry

    Angle a lies in the second quadrant and angle b lies in the third quadrant such that cos(a)=-3/5 and tan(b)=24/7. Determine an exact value for a) cos(a+b) b) sin(a-b) c) sin2a

  1. mathematics

    f(a)=sin2a(10^sin2a). find f'(a)

  2. Math

    Prove that (cos2A)÷ ( 1+sin2A) = (cotA -1) ÷ (cotA +1)

  3. trig/math

    If A is between 270degrees and 360degrees, and cos A=12/13, find the exact value of: sin2a, cos2a, sin1/2a, cos1/2a

  4. mth, trig

    Given cos a=-7/25 in quadrant II , and sin b=-12/13, in quadrant IV , find cos(a+b) and sin2a

  1. trigonometry

    Prove : 1 + Sin2A/ Cos2A = CosA + SinA / CosA- SinA

  2. Trig identities:(

    Sin4A - cos4A = sin2A - cos2A Can i just square root the left side??:O

  3. calculus

    x=2cosa-cos2a,y=2sina-sin2a

  4. math

    how do you solve this.prove: cos2A plus cosA divided by sin2A minus sinA equal to cos2A plus 1 divided by sinA

You can view more similar questions or ask a new question.