The specific heat of carbon (graphite) is 0.71 J/(g·°C). How much energy is given off as a 2 gram piece of graphite cools from 120°C to 20°C?

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.71 J/g C * 2 g * 100 C = 142 J

To calculate the amount of energy given off, we can use the formula:

Q = m * c * ΔT

Where:
Q is the energy given off (in Joules)
m is the mass of the material (in grams)
c is the specific heat capacity of the material (in J/(g·°C))
ΔT is the change in temperature (in °C)

Given:
m = 2 grams
c = 0.71 J/(g·°C)
ΔT = 120°C - 20°C = 100°C

Substituting the values into the formula:

Q = 2 g * 0.71 J/(g·°C) * 100 °C
Q = 142 J/(°C)

Therefore, the amount of energy given off as the 2 gram piece of graphite cools from 120°C to 20°C is 142 Joules.

To calculate the amount of energy given off when the graphite cools from 120°C to 20°C, you can use the formula:

Q = m * c * ΔT

Where:
Q is the amount of energy (in Joules)
m is the mass of the substance (in grams)
c is the specific heat capacity of the substance (in J/(g·°C))
ΔT is the change in temperature (in °C)

In this case, the mass of the graphite is 2 grams, the specific heat capacity is 0.71 J/(g·°C), and the change in temperature is (120°C - 20°C) = 100°C.

Now we can calculate the amount of energy:

Q = 2g * 0.71 J/(g·°C) * 100°C
Q = 142 J

Therefore, the amount of energy given off as the 2 gram piece of graphite cools from 120°C to 20°C is 142 Joules.