The volume of a cone is said to be 36pi. All that is told is the water level goes up to H/2.
What is the volume of the water?
V = (1/3)π r^2 h = 36π
r^2 h = 108
Now if we cut the height in half, then the radius is also cut in half
new volume = (1/3)π(r/2)^2 (h/2)
= (1/24)π r^2 h
= (1/24)π(108) = 9π/2
or
the volume of similar solids is proportional to the cube of their sides
so (1/2)^3 = 1/8
so the new volume is (1/8)(36π) = 9π/2
To find the volume of the water in the cone, you need to determine the height of the water first. Let's go through the steps to find the volume of the water:
Step 1: Find the total height of the cone (H):
From the given information, we know that the water level goes up to H/2. This means the total height of the cone is twice the water level, so H = 2(H/2). This simplifies to H = H.
Step 2: Find the radius of the cone (r):
To calculate the radius, we need additional information. Unfortunately, the radius is not given in the question. Without the radius, we cannot determine the exact volume of the water.
Please provide the radius of the cone, and I'll be happy to help you calculate the volume of the water.