What is the volume, in L, occupied by 3.260 moles of NO2 gas at STP conditions?
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PV = nRT
To find the volume occupied by a gas at STP (Standard Temperature and Pressure), you can use the ideal gas law equation: PV = nRT.
In this equation:
- P is the pressure of the gas (which is 1 atmosphere at STP).
- V is the volume of the gas.
- n is the number of moles of the gas.
- R is the ideal gas constant (0.0821 L·atm/(mol·K)).
- T is the temperature of the gas in Kelvin.
At STP, the temperature is 273.15 Kelvin.
Now, let's plug in the values into the equation and solve for V:
PV = nRT
(1 atm) V = (3.260 moles) (0.0821 L·atm/(mol·K)) (273.15 K)
V = (3.260 moles) (0.0821 L·atm/(mol·K)) (273.15 K) / (1 atm)
V ≈ 71.9 L
Therefore, the volume occupied by 3.260 moles of NO2 gas at STP conditions is approximately 71.9 liters.