How many joules of heat are required to raise the temperature of 550 g of water from 12°C to 18°C
q = joules needed = mass H2O x specific heat H2O x (Tfinal-Tinitial)
Is it 301.248
No. What did you multiply?
mass H2O = 550 g.
specific heat H2O = 4.184 J/g*C
Tfinal = 18 C
Tinitial = 12 C
To calculate the amount of heat required to raise the temperature of a substance, you can use the specific heat capacity formula:
Q = m * c * ΔT
Where:
Q is the amount of heat transferred (in joules),
m is the mass of the substance (in grams),
c is the specific heat capacity of the substance (in J/g°C), and
ΔT is the change in temperature (in °C).
In this case, we want to find the amount of heat (Q) required to raise the temperature of 550 g of water from 12°C to 18°C.
Given:
m (mass of water) = 550 g
ΔT (change in temperature) = 18°C - 12°C = 6°C
The specific heat capacity of water is approximately 4.18 J/g°C.
Now, let's plug the values into the formula:
Q = 550 g * 4.18 J/g°C * 6°C
Q = 13854 J
Therefore, approximately 13854 joules of heat are required to raise the temperature of 550 g of water from 12°C to 18°C.