a car A is 200m behind car B both are traveling in the same direction, initial velocity 25m/s starting their motion at the same time they accelerate at 30, car A overtook car B after 20sec this time car B was travelin at the velocity 27.gm/s, what was the acceleration of car A when it was about to overtake car B?
Your School SUBJECT is MATH.
To find the acceleration of car A when it was about to overtake car B, we can use the following steps:
Step 1: Calculate the final velocity of car A at the time it overtakes car B.
Since car A overtakes car B after 20 seconds, we can use the equation of motion:
v = u + at
where:
v = final velocity
u = initial velocity
a = acceleration
t = time
For car B, the final velocity is given as 27 m/s, the initial velocity is 25 m/s, and the time is 20 seconds.
So for car B, we have:
27 = 25 + a(20)
Step 2: Solve the equation for acceleration.
Rearrange the equation and solve for 'a':
a = (27 - 25) / 20
Simplifying, we get:
a = 2 / 20
a = 0.1 m/s²
Therefore, the acceleration of car A when it was about to overtake car B is 0.1 m/s².