A 6.0mc is placed at the origin and -4.0mc is placed at 2.0m to the right. What is the force on F1,F2? The first charge due to the presence of second charge ? What is the force on the second charge due to the presence of first charge?
To find the force between two electric charges, we can use Coulomb's Law, which states that the force between two charges is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. The equation for Coulomb's Law is:
F = k * (q1 * q2) / r^2
where F is the force between the charges, k is the electrostatic constant (k = 8.99 x 10^9 N*m^2/C^2), q1 and q2 are the magnitudes of the charges, and r is the distance between the charges.
In this case, we have a charge of 6.0mc (1 mc = 1 microcoulomb = 10^-6 C) at the origin and a charge of -4.0mc at a distance of 2.0m to the right. We can find the force on the first charge (F1) due to the presence of the second charge and the force on the second charge (F2) due to the presence of the first charge.
Calculating the force on F1 due to the presence of F2:
- Magnitude of F2 = k * (|q1| * |q2|) / r^2
- Plugging in the values:
F2 = (8.99 x 10^9 N*m^2/C^2) * (6.0 x 10^-6 C) * (4.0 x 10^-6 C) / (2.0m)^2
Calculating the force on F2 due to the presence of F1:
- Magnitude of F1 = k * (|q1| * |q2|) / r^2
- Plugging in the values:
F1 = (8.99 x 10^9 N*m^2/C^2) * (6.0 x 10^-6 C) * (4.0 x 10^-6 C) / (2.0m)^2
Note that the forces on each charge will have opposite directions since one charge is positive and the other is negative.
Simplifying the calculations will give you the numerical values of the forces on each charge due to the presence of the other charge.