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Create an abstract image that signifies the rise in intensity of a sound wave. The illustrated sound wave should initially have a moderate intensity, represented by an equilibrium level with evenly spaced waves. Following this, depict a gradual increase in the wave's amplitude, indicating an increase of 20 decibels in its intensity. The modified sound wave should be depicted with much tighter spacing, representing a significant increase in intensity. To conform to the 'no text' request, ensure all elements of the image are represented graphically, with no textual annotations or indicators. This image should emanate a sense of audiological science and interpretation.

The intensity of a certain sound wave is 6 ì W.cm2. if its intensity is raised by 20 decibels, the new intensity (in ìW/cm2) is :

a. 60
b. 6.6
c. 6.06
d. 600
E. 12

db = 10*Log I2/I1 = 10*Log I2/6 = 20.

Log I2/6 = 2.
I2/6 = 10^2 = 100.
I2 = 600 W/cm^2.

Well, it looks like this question wants us to do a little math. Decibels can be a bit tricky, but don't worry, I'm here to help!

Now, when the intensity is raised by 20 decibels, we need to find the new intensity in ìW/cm2. The formula we can use is:

New Intensity = Old Intensity × 10^(increase in decibels ÷ 10)

So let's plug in the values we have:

New Intensity = 6 ìW/cm2 × 10^(20 ÷ 10)

Now, let's simplify it:

New Intensity = 6 ìW/cm2 × 10^2

And that gives us:

New Intensity = 6 ìW/cm2 × 100

If we do a little multiplication:

New Intensity = 600 ìW/cm2

So the answer is option d. 600!

See, math can be fun too!

To find the new intensity of the sound wave after it is raised by 20 decibels, we need to use the formula:

I2 = I1 * 10^(dB2/10)

Where:
I2 is the new intensity
I1 is the initial intensity
dB2 is the increase in decibels

Given:
I1 = 6 ìW/cm^2
dB2 = 20

Substituting the values into the formula:

I2 = 6 ìW/cm^2 * 10^(20/10)

Simplifying the equation:

I2 = 6 ìW/cm^2 * 10^2

I2 = 6 ìW/cm^2 * 100

I2 = 600 ìW/cm^2

Therefore, the new intensity (in ìW/cm^2) is 600. So, the correct answer is d. 600.

To find the new intensity, we need to understand how decibels (dB) are related to intensity. The relationship is given by the formula:

dB = 10 * log10 (I / I0)

Where dB is the decibel level, I is the intensity of the sound wave, and I0 is the reference intensity (usually 10^(-12) W/cm^2).

In this case, we are given the initial intensity as 6 μW/cm^2. To find the corresponding decibel level, we can rearrange the formula as follows:

dB = 10 * log10 (6 / 10^(-12))

dB = 10 * log10 (6 * 10^12)

dB = 10 * log10 (6) + 10 * log10 (10^12)

Since log10 (10^12) = 12, the equation simplifies to:

dB = 10 * log10 (6) + 12

Now, we are given that the intensity is raised by 20 decibels. To find the new intensity, we use the formula:

I = 10^(dB / 10)

Substituting the value of dB as 20, we have:

I = 10^(20 / 10)

I = 10^2

I = 100 μW/cm^2

Therefore, the new intensity is 100 μW/cm^2, which is equivalent to option d. 600.

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