M = mols/L; therefore,
# mols = M x L
You have M = 0.100 and you have L - 0.100 so you want 0.01 mols of the base and 0.01 mols of the salt (the acid) (since the problem states you want an equimolar solution of base and acid.
After you know mols, then mols = grams/molar mass. You know molar mass and you know the mols, calculate grams of the base and grams of the salt (acid). Voila!
Tris is an abbreviation for tris (hydroxymethyl) aminomethane, which is a weak base. Calculate how many grams of tris (mw=121.14g/mol) are needed to make 25mL of 0.10M tris solution. Calculate how many mL of 0.25M HCl are needed
How do you prepare 100 mL of a 0.1 M TRIS-HCl buffer with a pH 7.4 using solid TRIS base (MW 121.1) and 1 M hydrochloric acid? I started with pH=pKa + log ([Tris]/[Tris+] [Tris]/[Tris+]= 10^(7.4-8.06]=0.219 so 0.219:1 ratio with
Prepare 1.5 liters of 0.25 M Tris buffer, pH 7.5. Useful information: pKa Tris = 8.1 Formula weight of Tris (hydroxymethyl aminomethane) base = 121.1 Formula weight of Tris hydrochloride (acid form) = 158.0
Calculate the pH of a solution prepared by dissolving 10.0 g of tris(hydroxymethyl)aminomethane ("tris base") plus 10.0 g of tris hydrochloride in 0.250 L of water. (a) What will be the pH if 10.5 mL of 0.500 M NaOH is added?
what is the pH of the buffer when 4ml of 1M HCl is added to a 100ml buffer solution made using 5ml 1M Na2HPO4 and 5ml 1M NaH2PO4? The pKa for H+ + HPO4- ==> H2PO4 is 6.82. What would happen to the pH if the 100ml buffer had been
Tris(hydroxymethyl)aminomethane, commonly called TRIS or Trizma, is often used as a buffer in biochemical studies. Its buffering range is pH 7 to 9, and Kb is 1.19 10-6 for the following aqueous reaction. (HOCH2)3CNH2 + H2O