The sum of three consecutive natural numbers is 966. Find the numbers.
X, (X+1), (X+2).
x + (x+1) + (x+2) = 966.
3x + 3 = 966.
3x = 963.
X = 321.
X+1 = 322.
X+2 = 323.
Well, let's call the first number "x". Then the next two consecutive natural numbers would be "x+1" and "x+2". Now, to find their sum, we add them up: x + (x+1) + (x+2) = 3x + 3.
Given that the sum is 966, we can set up the equation: 3x + 3 = 966.
Now, let's solve for x: 3x = 963, x = 321.
So, the three consecutive natural numbers would be 321, 322, and 323.
But seriously, why did the numbers have to make it so difficult for us? They could have just arranged themselves neatly in a line and said, "Hey, we sum up to 966!". Oh well, at least we got the answer!
Let's assume that the first natural number is x.
According to the problem, the sum of three consecutive natural numbers can be expressed as:
x + (x+1) + (x+2) = 966
Combining like terms, we can simplify the equation to:
3x + 3 = 966
Now, let's solve this equation for x.
Subtract 3 from both sides:
3x = 966 - 3
3x = 963
Divide both sides by 3:
x = 963 / 3
x = 321
Therefore, the first natural number is 321.
To find the other two numbers, we can substitute the value of x into the equation:
321 + 1 = 322 (second number)
321 + 2 = 323 (third number)
So, the three consecutive natural numbers are 321, 322, and 323.
To find the three consecutive natural numbers whose sum is 966, we can set up an equation. Let's assume that the first natural number is "x".
So, the three consecutive natural numbers would be x, x+1, and x+2 because they are consecutive to each other.
Now we can write the equation:
x + (x+1) + (x+2) = 966
Simplifying the equation:
3x + 3 = 966
Subtracting 3 from both sides of the equation:
3x = 963
Finally, dividing both sides of the equation by 3:
x = 321
So the three consecutive natural numbers are 321, 322, and 323.
Let x be the middle number
x-1 + x + x+1 = 966
3x = 966
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