What is the mass, in grams, of a sample of solid zinc if its temperature changes from 25.7oC to 39.0oC when it absorbs 123 J of heat energy?
Specific heat of zinc = 0.388 J/(g oC)
q = mass Zn x sp.h. Zn x (Tf-Ti)
Substitute and solve for mass Zn.
To calculate the mass of the sample of solid zinc, we can use the equation:
Q = m * c * ΔT
Where:
- Q is the heat energy absorbed (in Joules)
- m is the mass of the sample (in grams)
- c is the specific heat of zinc (in J/(g oC))
- ΔT is the change in temperature (in oC)
In this case, the given values are:
- Q = 123 J
- c = 0.388 J/(g oC)
- ΔT = 39.0 oC - 25.7 oC = 13.3 oC
Substituting these values into the equation, we can solve for the mass (m):
123 J = m * 0.388 J/(g oC) * 13.3 oC
To isolate m, we can rearrange the equation:
m = 123 J / (0.388 J/(g oC) * 13.3 oC)
m ≈ 7.521 grams
Therefore, the mass of the sample of solid zinc is approximately 7.521 grams.