1)An electronic repair shop has 5 vacum cleaners, 12 tv sets, and 18 vcrs to be repaired. The store employs two part time repairmen. One repairman can repair at least one vacum cleaner, three tv sets and three vcrs in 1 week. While the second repairman can repair at least one vacum cleaner, two tv sets and six vcrs in 1 week. The first employee is paid $250 a week and the second is paid $220 a week. To minimise the cost (in terms of wages paid), how many weeks should each of the two repairman be employed.

Question

1)An electronic repair shop has 5 vacum cleaners, 12 tv sets, and 18 vcrs to be repaired. The store employs two part time repairmen. One repairman can repair at least one vacum cleaner, three tv sets and three vcrs in 1 week. While the second repairman can repair at least one vacum cleaner, two tv sets and six vcrs in 1 week. The first employee is paid $250 a week and the second is paid $220 a week. To minimise the cost (in terms of wages paid), how many weeks should each of the two repairman be employed.

(please outline the objective function and the constraints) :)
Jah bless

Answer 1

I managed to attempt...not sure if correct thou.

Vacum tv vcr = cost
X-repairmen 1 ...1 3 3 = 250x
y-repairmen 2 ...1 2 6 = 220y
5 12 18
1) find optimization
c = 250x + 220 y

2) find constraints
X+y》5 , 3x+2y》5, 3x+6y》18, x>0,y>0

3) find x & y int
A) (5,0) (0,50 b)(1.67,0) (0,2.5)
C) (6,0) (0,3)

4) find mid point
Solve equation x+y=5 & 3x+6y= 18..
So x=4 & y=1

Wanna know if m on right track