A bullet leaves the barrel of a rifle with a speed of 300m/s. If the length of the barrel is 0.9m, at what rate is the bullet accelerated while in the barrel?
Your school SUBJECT is probably PHYSICS.
632 m/s^2
Yes
To find the rate at which the bullet is accelerated while in the barrel, we can use the concept of average acceleration. Average acceleration is defined as the change in velocity (Δv) divided by the time interval (Δt):
Average acceleration (a) = Δv / Δt
In this case, the initial velocity of the bullet is 0 m/s (since it starts from rest in the barrel) and the final velocity is 300 m/s. The time interval can be calculated using the formula:
Δt = d / v
Where d is the distance traveled and v is the final velocity. In this case, the distance traveled in the barrel is given as 0.9 m.
Δt = 0.9 m / 300 m/s
Now, we can substitute the values into the average acceleration formula:
a = (300 m/s - 0 m/s) / (0.9 m / 300 m/s)
Simplifying the equation gives us:
a = 30000 m^2/s^2 / 0.9 m
a = 33333.33 m/s^2
Therefore, the bullet is accelerated at a rate of approximately 33333.33 m/s^2 while in the barrel.
We can use the formula:
vf^2 - vo^2 = 2ad
where
vf = final velocity
vo = initial velocity
a = acceleration
d = distance
Substituting,
300^2 - 0^2 = 2(a)(0.9)
a = ?
Now solve for a. Units in m/s^2
Hope this helps~ `u`