A street that is
155m
long is covered in snow. City workers are using a snowplow to clear the street. The snowplow has tires that are
1.5m
in diameter. How many times does a tire have to turn in traveling the length of the street?
Use the value
3.14
for
π
. Round your answer to the nearest tenth. Do not round any intermediate steps.
C = pi * d
C = 3.14 * 1.5
C = 4.71
155 * 4.71 = 730.05 = 730.1 times
ah, I think 155 / C
Ahhh! You're right, Damon. I goofed! :-(
Thanks for rescuing this post.
Pure luck ! You are welcome :)
To find out how many times a tire has to turn in traveling the length of the street, we need to calculate the distance each tire covers in one complete revolution and then divide the length of the street by that distance.
First, let's find the circumference of the tire. The circumference of a circle can be calculated using the formula:
C = π * d
where C is the circumference and d is the diameter. Plugging in the given values, we have:
C = 3.14 * 1.5
C ≈ 4.71 meters
So, in one revolution, the tire covers approximately 4.71 meters.
Next, we can calculate how many times the tire has to turn in traveling the length of the street. We divide the length of the street by the distance covered in one revolution:
Number of turns = Length of street / distance covered in one revolution
Number of turns = 155 / 4.71
Number of turns ≈ 32.94
Rounding to the nearest tenth, the tire has to turn approximately 32.9 times in traveling the length of the street.