If 5X + x squared > 100 then x is not equal to
Online "^" is used to indicate an exponent, e.g., x^2 = x squared.
Could be any of a multitude of numbers. What are your choices?
this isn't so hard
7^2+5*7 = 49+35 = 84 < 100
8^2+5*8 = 64+40 = 104 > 100
So, any x, 8 or above, will satisfy the inequality.
If any of your choices is less than 8 (or so), it won't work. Of course, if x is negative, there are other possibilities.
To determine the values of x that satisfy the inequality 5x + x^2 > 100, we can follow these steps:
1. Rearrange the inequality to get it in the form of a quadratic equation: x^2 + 5x - 100 > 0.
2. To solve this quadratic inequality, we need to find the x-values that make the expression greater than zero. To do this, we can factor the quadratic equation or use the quadratic formula.
3. Factoring the quadratic equation: (x - 5)(x + 20) > 0.
4. Now we have two factors, (x - 5) and (x + 20). To determine the sign of the inequality, we can use a sign chart or the concept of intervals.
5. Consider each factor separately and determine when it is positive (greater than zero).
For (x - 5) > 0, we find x > 5.
For (x + 20) > 0, we find x > -20.
6. Combine the intervals by taking the intersection between the two intervals. Since the factors have different signs, we need to consider the intervals where both factors are positive.
The overlapping interval is x > 5.
7. Therefore, the solution to the inequality 5x + x^2 > 100 is x > 5. This means that any value of x that is greater than 5 will satisfy the inequality.