If the sides of the rectangle are (fq-8)dm and (f^2g^2 + 8fg + 64) dm. what is the area of the rectangle ?
Please Help me :\ and thank you for those who answer :)
(fg-8)(f^2g^2 + 8fg + 64)
This is just the difference of two cubes:
(fg)^3 - 8^3
Recall that
(a^3-b^3) = (a-b)(a^2+ab+b^2)
You have
a = fg
b = 8
a = fg+b = 8
To find the area of a rectangle, you multiply the length of one side by the length of the other side. In this case, the sides of the rectangle are given as (fq-8) dm and (f^2g^2 + 8fg + 64) dm, respectively.
So, to calculate the area, you need to multiply these two expressions together:
Area = (fq-8) * (f^2g^2 + 8fg + 64)
Now, you can perform the multiplication and simplify the expression to find the area. However, since the values of f and g are unknown, it is not possible to calculate an exact numerical value for the area without knowing the values of f and g.