one number is 8 less than another. If twice the larger number is equal to four times the smaller number.what is the smaller number?
x = y-8
2y = 4x
Now do a little substitution for y, and you can easily find x.
thank you
just a little nudge can usually help.
To solve this problem, we can set up two equations based on the given information.
Let's assume the larger number is "x" and the smaller number is "y."
According to the problem, "one number is 8 less than another," can be translated into the equation:
x = y + 8 (Equation 1)
It is also given that "twice the larger number is equal to four times the smaller number." This can be translated into the equation:
2x = 4y (Equation 2)
Now we have a system of two equations:
x = y + 8
2x = 4y
To find the value of the smaller number (y), we can solve this system of equations using substitution or elimination method.
Let's use substitution method to solve the equations. We can substitute the value of x (from Equation 1) into Equation 2:
2(y + 8) = 4y
2y + 16 = 4y
Now, subtract 2y from both sides:
16 = 2y
Finally, divide both sides by 2:
y = 8
Therefore, the smaller number is 8.