what is the KE of a 0.2kg rolling ball travelling at a speed of 5m/s
(1/2) m v^2 = .5*.2*25 Joules
although it also has rotational energy Kinetic spin energy = (1/2)I omega ^2
= (1/2)(2/5) (.2)(R^2) omega^2
but v = R omega
so add
(1/2) (2/5)(.2) (25)
To find the kinetic energy (KE) of the rolling ball, you need to use the formula:
KE = 1/2 * m * v^2
Where:
- KE is the kinetic energy
- m is the mass of the ball (0.2kg in this case)
- v is the velocity of the ball (5m/s in this case)
Now, we can substitute the values into the formula and solve it:
KE = 1/2 * 0.2kg * (5m/s)^2
= 1/2 * 0.2kg * 25m^2/s^2
= 2.5 Joules
Therefore, the kinetic energy of the ball is 2.5 Joules.