In all parts: assume the the air temperature is 17.8o C, so the speed of sound in air is 342.0 m/s.
Part A. Suppose a ship's foghorn is sounded toward an iceberg, and an echo is heard 6.16 s later. Find the distance from the ship to the iceberg.
d = ? m
Part B. b) Suppose the lab floor is 2.21 m beneath the motion detector. If the detector produces a click and the sound bounces off the floor, how long would it take between the creation of the sound and the echo returning to the sensor?
t = ? s
A. So, how far does sound travel in 6.16 seconds? That is the round trip, so the berg is half that far away.
B. same problem in reverse. How long to make a round trip of 2*2.21 meters?
distance = speed * time
time = distance/speed
Thank you Steve!
Part A: To find the distance from the ship to the iceberg, we can use the fact that the speed of sound is 342.0 m/s. The total time it takes for the sound to travel to the iceberg and back as an echo is 6.16 seconds.
Since the sound has to travel to the iceberg and then back, we can divide the total time by 2 to find the time it takes for only one leg of the journey. This will give us the time it takes for the sound to travel from the ship to the iceberg, or vice versa.
t = 6.16 s / 2
t = 3.08 s
Using the speed of sound formula, we can solve for the distance (d):
distance = speed * time
d = 342.0 m/s * 3.08 s
d ≈ 1053.36 m
Therefore, the distance from the ship to the iceberg is approximately 1053.36 meters.
Part B: Given that the lab floor is 2.21 m beneath the motion detector, we need to find the time it takes for the sound to travel from the motion detector to the floor and then back to the sensor.
Since the sound has to travel to the floor and then back, we can again divide the total time by 2 to find the time it takes for only one leg of the journey.
t = total time / 2
t = ? s / 2
However, we don't have the total time given in the question, so we need more information to calculate the time taken for the echo to return to the sensor.