A total of 598 tickets were sold for the school play. They were either adult tickets or student tickets. There were 52 fewer student tickets sold than adult tickets. How many adult tickets were sold?
a + s = 598
s = a - 52
sub s = a-52 into the first equation
a + a-52 = 598
2a = 650
a = 325
s = 325-52 = 273
325 adult and 273 student
Well, it seems like those student tickets were just a little shy. They sold 52 fewer than the adult tickets, which means they were probably hiding in the back row. To find out how many adult tickets were sold, we can do a little math. Let's say the number of adult tickets sold is A. Since there were 52 fewer student tickets sold, we can say that the number of student tickets sold is A - 52. And if we add up the total number of tickets, we get A + (A - 52) = 598. So, solving this puzzle, we find that the number of adult tickets sold is 325. So, it looks like the adults were ready for a night of culture and fun!
Let's assume the number of adult tickets sold is x.
Since there were 52 fewer student tickets sold than adult tickets, the number of student tickets sold would be x - 52.
The total number of tickets sold for the school play is 598.
So, the equation to represent the situation is x + (x - 52) = 598.
Simplifying the equation, we have 2x - 52 = 598.
Adding 52 to both sides of the equation, we get 2x = 650.
Dividing both sides of the equation by 2, we find x = 325.
Therefore, 325 adult tickets were sold.
To find the number of adult tickets sold, we need to set up an equation based on the given information.
Let's assume the number of adult tickets sold is 'x'. According to the problem, 52 fewer student tickets were sold than adult tickets. So, the number of student tickets sold would be 'x - 52'.
Now, the total number of tickets sold is given as 598. So, we can set up the equation:
x + (x-52) = 598
Simplifying the equation, we have:
2x - 52 = 598
2x = 650
x = 325
Therefore, 325 adult tickets were sold for the school play.