1. JUGGLING NUMBERS
From old newspapers cut out digits 0 to 9 and stick them in a creative manner. Make sure the digits are not too small. Juggle the digits to make the numbers described below.
The challenge is you can use a digit only once in a number.
1) Make the smallest number using all the digits.
2) Make the greatest number using all the digits.
3) Make the greatest possible number that is greater than 8000 but less than 8500.
4) Make the smallest number that is greater than 4316.
5) Make the number which comes between 4999 and 5001.
6) Make the successor of 2090.
7) Make the predecessor of 8000.
I want all the answer please help me I want to submit this project.
I hop kindly you help me above given question?
I want all the answers
Surely you can play around with the digits on this. For example,
(1) Assuming no leading zero, that would be 1023456789
(4) The smallest number greater than 4316. That would be 4317.
Are there really any that cause you difficulty? We can check your answers.
2oo5
To solve these juggling number problems, we will use the given digits 0 to 9 and follow certain rules:
1) To make the smallest number using all the digits, we need to start with the digit that has the smallest value and arrange the remaining digits in ascending order. The arrangement will be 0 at the beginning followed by 1, 2, 3, 4, 5, 6, 7, 8, and 9. So the smallest number using all the digits is 0123456789.
2) To make the greatest number using all the digits, we need to start with the digit that has the largest value and arrange the remaining digits in descending order. The arrangement will be 9 at the beginning followed by 8, 7, 6, 5, 4, 3, 2, 1, and 0. So the greatest number using all the digits is 9876543210.
3) To make the greatest possible number that is greater than 8000 but less than 8500, we need to focus on the thousands digit. Since the number needs to be greater than 8000, the thousands digit can be either 8 or 9. However, it needs to be less than 8500, so we choose 8. The remaining digits will be arranged in descending order. The arrangement will be 8 at the beginning followed by 7, 6, 5, 4, 3, 2, 1, and 0. So the greatest possible number that meets these conditions is 8765432108.
4) To make the smallest number that is greater than 4316, we need to focus on the digits starting from the thousands place. Since the given number is 4316, we need to replace the digits starting from the hundreds place. We can change the hundreds digit to 4, then arrange the remaining digits in ascending order. So the smallest number greater than 4316 using all the digits is 4320175896.
5) To make the number that comes between 4999 and 5001, we need to focus on the ones place. Since the number needs to be between 4999 and 5001, the ones digit can be either 0 or 1. The remaining digits can be arranged in any order. So a number between 4999 and 5001 using all the digits could be 4907168253 or 4107698253.
6) To make the successor of 2090, we need to add 1 to it. So the successor of 2090 is 2091.
7) To make the predecessor of 8000, we need to subtract 1 from it. So the predecessor of 8000 is 7999.
Using these rules, you can solve the juggling numbers problems and find the required numbers using the given digits.