what work is done in raising a 3.0 kg mass from a 2.5 m high ledge to a 6.5 m high shelf?

How much potential energy (Ep) does the mass now posses?

Ok so for part 1 its w = m g h

w = (3.0kg)(10m/s^2)(6.5m-2.5m)

w = 120J

now how do you find the potential energy?

weight(force) = mg

Ep = mgh

work = force*distance
You found the work, which is just ∆Ep

work and energy are the same units.

All yo can really find in this world is DIFFERENCES in potential energy.

In this case, whoever wrote the question probably expected you to define zero potential at the FLOOR
so the h you use for part 1 which is 6.5 -2.5 = 4
is NOT the h you use for part 2
for part 2, use the full height of 6.5 meters

The question is trying to be tricky, but in fact is poorly worded.

To find the potential energy (Ep) of the mass after it has been raised, you can use the formula:

Ep = m * g * h

where m is the mass of the object (3.0 kg), g is the acceleration due to gravity (approximately 10 m/s^2), and h is the height above a reference point (6.5 m).

Plugging in the values, we have:

Ep = (3.0 kg) * (10 m/s^2) * (6.5 m)

Ep = 195 J

Therefore, the potential energy of the mass after it has been raised to the 6.5 m high shelf is 195 Joules (J).