# Physics

A car, moving along a straight stretch of highway, begins to accelerate at 0.0442 m/s^2. It takes the car 30.8 s to cover 1 km. How fast was the car going when it first began to accelerate?

I tried converting 30.8 km/sec to m/s then subtracting 0.0442, but I got -0.0134, and it can't be a negative. I've also tried the answers 30799.558, 13.4, and 0.0134 but my online homework sheet has said they are all wrong. Thanks for the help!

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1. Here what i did.
a=0.0442 m/s^2
t1=30.8 s
d=1 km =1000 m.
find the initial velocity (speed)=Vo when car starts accelerating.

From basic equation of acceleration,
a = dv/dt = (V1-Vo)/(t1-t0) ; t0= 0s.

Vo = V1 - a.t1

missing V1=d/t0 = 1000/30.8 = 32.46 m/s.
Then, Vo = 32.46 - (0.0442)(30.8)
=31.1 m/s

tell me answer is correct or not.

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2. jzee11 that answer wasn't right. I had the exact same numbers as the OP and it said that answer was wrong

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