Kanchan spends 1/2 of her money in one shop .she spends 1/3 of what was left with her on rickshaw fare. At the end she has rs 20 with her .how much did she have in the beginning?
Let's assume that Kanchan had Rs. X in the beginning. According to the given information:
Step 1: Kanchan spends 1/2 of her money in one shop. So, the amount left with her after this spending is (X - 1/2*X) = 1/2*X.
Step 2: From the remaining amount, she spends 1/3 on a rickshaw fare. So, the amount left with her after this spending is (1/2 * X - 1/3 * 1/2 * X) = (1/2 * X - 1/6 * X) = 1/3*X.
Step 3: At the end, she has Rs. 20 left. So, we can equate 1/3*X = 20.
Solving the equation:
1/3 * X = 20
X = 20 * 3
X = 60
Therefore, Kanchan had Rs. 60 in the beginning.
To find out how much money Kanchan had in the beginning, we can work backwards from the given final amount. Let's follow these steps:
Step 1: Let's assume that Kanchan's initial amount of money is "x" rupees.
Step 2: Kanchan spends 1/2 of her money in a shop. So she has (1/2)x rupees left.
Step 3: She further spends 1/3 of what she had left on rickshaw fare. Therefore, she has (1 - 1/3) * (1/2)x rupees left.
Step 4: According to the given information, Kanchan has 20 rupees left at the end. So, we can equate the expression above to 20 and solve for x.
(1 - 1/3) * (1/2)x = 20
Simplifying the equation:
(2/3) * (1/2)x = 20
(1/3)x = 20
Multiplying both sides by 3:
x = 60
So, Kanchan had 60 rupees in the beginning.
60 answer
ayega
starts with x
spends half, so amount left = (1/2)x
Spends 1/3 of that, so left with (2/3)of (1/2)x
thus amount left = (2/6)x or (1/3)x
but (1/3)x = 20
x = 60