x^2 + 2x + 2 = 0

The answer has an imaginary number in it which we're supposed to solve for, but I'm having trouble with it.

Thanks for any help!

x^2 + 2x + 2 = 0

I would use "completing the square"

x^2 + 2x = -2
x2 + 2x + 1 = -2+1
(x+1) = -1
x+1 = ±√-1, remember √-1 = i
x = -1 ± i

(x^2 + 2x + 2) -1 = (0)-1

x^2 + 2x +1 = -1
(x + 1)(x + 1) = -1
(x +1)^2 = -1
(x +1) = sr(-1) (sr squareroot of)
x = -1 + sr(-1)

To solve the quadratic equation x^2 + 2x + 2 = 0 which has an imaginary solution, you can use the quadratic formula. The quadratic formula is given by:

x = (-b ± √(b^2 - 4ac)) / (2a), where a, b, and c are the coefficients of the quadratic equation in the form ax^2 + bx + c = 0.

In our case, a = 1, b = 2, and c = 2. Substituting the values into the quadratic formula, we get:

x = (-2 ± √(2^2 - 4(1)(2))) / (2(1))
= (-2 ± √(4 - 8)) / 2
= (-2 ± √(-4)) / 2

Since we have a negative value inside the square root, we can simplify it using the imaginary unit "i" which is defined as √(-1). Therefore,

√(-4) = 2i

Substituting the value back into the equation, we have:

x = (-2 ± 2i) / 2
= -1 ± i

Hence, the solutions to the quadratic equation x^2 + 2x + 2 = 0 are:

x = -1 + i
x = -1 - i

To solve the given quadratic equation, x^2 + 2x + 2 = 0, we can use the quadratic formula. The quadratic formula allows us to find the solutions for any quadratic equation in the standard form ax^2 + bx + c = 0, where a, b, and c are constants.

The quadratic formula states that for any quadratic equation ax^2 + bx + c = 0, the solutions can be found using the following formula:

x = (-b ± √(b^2 - 4ac)) / (2a)

In our case, a = 1, b = 2, and c = 2. Substituting these values into the quadratic formula, we get:

x = (-2 ± √(2^2 - 4*1*2)) / (2*1)

Simplifying further:

x = (-2 ± √(4 - 8)) / 2

x = (-2 ± √(-4)) / 2

Here, we encounter an imaginary number, since the square root of a negative number is represented by the imaginary unit "i." The square root of -4 is 2i, so our equation becomes:

x = (-2 ± 2i) / 2

Simplifying further:

x = -1 ± i

Thus, the solutions to the equation x^2 + 2x + 2 = 0 are x = -1 + i and x = -1 - i.