I need help for this question. I also need an explanation.The answer says log3(3x^2) but I need an explanation.
1 + log3(x^2)
Math - Steve, Saturday, June 27, 2015 at 6:51pm
I'm not Carnak the Magnificent. What was the question, and how did you arrive at your answer?
We're willing to provide help, and even answers, but don't make us come up with the questions, too!!
Math - Ms. Sue, Saturday, June 27, 2015 at 6:58pm
<g>
Math - Anonymous, Saturday, June 27, 2015 at 8:58pm
1 + log3(x^2) is the question. I posted it up there.
Math - Anonymous, Saturday, June 27, 2015 at 8:59pm
I didn't get the answer. I looked at the back of the textbook for the answer.The answer from the back of the textbook was log3(3x^2). I just need to know how to get the answer.
1 + log3(x^2) is not a question
1 + log3(x^2) is an algebraic expression
What do you want to do with it ?
Do you want to solve something like 1 + log3(x^2) = 0 ?
Do you want to colour it blue?
Do you want to sent it to Donald Trump as a campaign slogan?
etc
The way it stands, I agree with Steve. Your "question" makes no sense
I got this from the textbook. Write each expression as a single logarithm. Assume that all the variables represent positive numbers. 1+log3(x^2). The answer in the back is log3(3x^2).
Just thought I would play some "Jeopardy" with your post
Alex Trebek : log3 (3x^2)
me: What is 1 + log3 (x^2) simplified
expanation:
log3 (3x^2)
= log3 3 + log3 (x^2)
= 1 + log3 (x^2)
so the two expressions are the same.
sorry, I'll post the entire question next time.
looks like our replies crossed.
So there was an actual direction to your problem.
Now you state:
"Write each expression as a single logarithm"
Why didn't you say that at the beginning and avoid all this confusion.?
To explain how to get the answer for the expression 1 + log3(x^2), we need to understand the rules of logarithms.
First, let's recall that the logarithm in base 3 (log3) is the exponent to which 3 must be raised to obtain a given number. In this case, the number is (x^2).
The expression 1 + log3(x^2) can be rewritten as log3(3) + log3(x^2) using the property of logarithms that states loga(b) + loga(c) = loga(bc).
Now, applying the rule of logarithms that states loga(a) = 1, we have log3(3) + log3(x^2) = 1 + log3(x^2).
Since log3(3) equals 1, we can simplify the expression to 1 + log3(x^2) = log3(3) + log3(x^2) = log3(3x^2).
Therefore, the final answer to the expression 1 + log3(x^2) is log3(3x^2).