How many moles of carbon are found in 250.0 g of CaCO3?

I started off with finding the molar mass of CaCO3, which is 100.09g. From there I divided 250g by 100.09g, but I have no idea what to do from there.

ok, at that point you know how many moles of CaCO3 you have. Now look at the formula: for each mole of CaCO3, there is one mole of C.

Moles of C=250.0/100.1 to four decimal places (if your mole mass is correct)

If there is one mole of Carbon for every CaCO3, all I had to do was divide it and that would be my answer (2.498)? What if it was 2 moles of carbon instead of one, what would I have to do then?

What you have done now is

mols CaCO3 = g/molar mass = 250/100.09 = 2.498 mols.
Then convert from mols CaCO3 to mols C.
2.498 x (1 mol C/1 mol CaCO3) = 2.498 x 1/1 = 2.498 mols C.

Suppose the formula for CaCO3 was CaC2O3 (strictly a fictitious compound).
Then mols CaC2O3 in 250 g is 250/112.1 = 2.230. Now convert to mols C
2.230 mols CaC2O3 x (2 mols C/1 mol CaC2O3) = 2.230 x 2/1 = ?

Just to recap:

I divide the grams of the compound by its molar mass. From there, I do the mol conversion from CaCO3 to C and that will by my answer.

yes. It's two steps.

1. Convert grams you have to mols.
2. Convert mols of what you have to mols of what you want.

To find the number of moles of carbon in 250.0 g of CaCO3, you are on the right track by first calculating the molar mass of CaCO3 as 100.09 g/mol.

Next, we need to determine the molar mass of carbon (C). Carbon has an atomic mass of approximately 12.01 g/mol.

Now we can set up a conversion factor to calculate the number of moles of carbon:

1 mole of CaCO3 = 1 mole of carbon

Using the molar mass of C, we can calculate the number of moles of carbon in 250.0 g of CaCO3:

250.0 g CaCO3 × (1 mol CaCO3/100.09 g CaCO3) × (1 mol C/1 mol CaCO3) × (12.01 g C/1 mol C)

Let's simplify this calculation step by step:

Step 1: Convert grams of CaCO3 to moles of CaCO3

250.0 g CaCO3 × (1 mol CaCO3/100.09 g CaCO3) = 2.498 mol CaCO3

Step 2: Convert moles of CaCO3 to moles of carbon

2.498 mol CaCO3 × (1 mol C/1 mol CaCO3) = 2.498 mol C

Step 3: Calculate grams of carbon

2.498 mol C × (12.01 g C/1 mol C) = 30.01 g C

Therefore, there are approximately 2.498 moles of carbon in 250.0 g of CaCO3.