A 30 kg sled is pulled at constant speed with a horizontal rope for a distance of 450 m. The coefficient of friction is 0.15. Find the work done by the applied force on the rope.
it looks like this means we have to find the applied force in newtons before we can solve this. how does one find the applied force?
since the sled is not accelerating, the net force acting on it must be zero.
So, since the friction is .15*(30*9.8), that is equal to the force acting on the sled.
still not getting the right answer. help solve this?!
work done=forceapplied*distance
=.15*30*9.8*450 Joules
thanks !!!!
To find the applied force, you can use Newton's second law of motion, which states that force is equal to mass multiplied by acceleration (F = ma). In this case, since the sled is pulled at a constant speed, the acceleration is zero. Therefore, the net force on the sled is also zero.
The net force acting on the sled is the sum of the applied force and the force of friction. The force of friction can be calculated using the coefficient of friction (μ) and the normal force (N), which is equal to the weight of the sled (mg).
The formula for frictional force is Ffriction = μN.
In this case, the weight of the sled (mg) is equal to (30 kg)(9.8 m/s^2) = 294 N.
Substituting the values into the formula for frictional force, Ffriction = (0.15)(294 N) = 44.1 N.
Since the net force is zero, the applied force must be equal to the force of friction in the opposite direction. Therefore, the applied force is 44.1 N.
With the applied force determined, you can now calculate the work done by this force using the equation work = force * distance.