Write y = 0.2x – 0.3 in standard form using integers.

standard form is Ax+By=C

You can rearrange things to have

0.2x - y = 0.3

That's close, but we want integers. Now, how do you get rid of those pesky decimals?

-2x+10y=-3

AMOSC @Sierra_h2004

To write the given equation, y = 0.2x - 0.3, in standard form using integers, we need to eliminate the decimal.

First, let's get rid of the decimal by multiplying the equation by 10. Since 10 is the least common multiple of 10 and 1 (the denominators of 0.2 and 0.3), multiplying by 10 will remove the decimal from both coefficients.

By multiplying through by 10, the equation becomes:
10y = 2x - 3

Next, let's bring all the terms to one side of the equation, and rearrange them in a standard form, which is Ax + By = C, where A, B, and C are integers.

So, let's subtract 2x from both sides and add 3 to both sides:
-2x + 10y = -3

Hence, the standard form of the given equation, y = 0.2x - 0.3, using integers is -2x + 10y = -3.

Afta arangin it in d form of ax +by=c . . 0.2x =2x/10

2x/10 - y=0.3
Afta doin Lcm 2x -10y divided by 10 =0.3 . . 2x -10y =0.3 x 10 =3 . Therefore ans = 2x -10y =3

um i think its 6