Hi guys. I cannot figure out how to do this question. Can you please do all the working out. Thanks

How many moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminum oxide, Al2O3?

Sure! To solve this problem, we'll use the balanced chemical equation for the formation of aluminum oxide, Al2O3:

4 Al + 3 O2 → 2 Al2O3

From the equation, we can see that it takes 4 moles of Al atoms to react with 3 moles of O atoms to produce 2 moles of Al2O3.

Given that there are 1.58 mol of O atoms, we can set up a proportion to find the number of moles of Al atoms required:

(4 mol Al / 3 mol O) × 1.58 mol O = x mol Al

Simplifying the equation, we have:

4/3 × 1.58 = x

x ≈ 6.6 mol Al

Therefore, approximately 6.6 moles of Al atoms are needed to combine with 1.58 mol of O atoms to make aluminum oxide, Al2O3.

Of course! To find out how many moles of Al atoms are needed to combine with 1.58 mol of O atoms to produce Al2O3, we need to use the balanced equation for the reaction between aluminum and oxygen.

The balanced chemical equation for the formation of aluminum oxide is:

4 Al + 3 O2 -> 2 Al2O3

From the balanced equation, we can see that 4 moles of aluminum react with 3 moles of oxygen to produce 2 moles of aluminum oxide. By comparing the ratio of oxygen and aluminum in the balanced equation, we can determine the number of moles of Al atoms needed.

To find the moles of Al atoms, we can set up a ratio:

(4 moles of Al) : (3 moles of O) = x : 1.58 moles of O

To solve for x (the number of moles of Al), we can use the following equation:

x = (4 moles of Al / 3 moles of O) * (1.58 moles of O)

Simplifying the expression:

x = (4/3) * 1.58 ≈ 2.107 moles of Al

Therefore, approximately 2.107 moles of Aluminum (Al) atoms are needed to combine with 1.58 moles of Oxygen (O) atoms to produce aluminum oxide (Al2O3).

0.26546666666...... I.e., 0.27

4Al + 3O2 ==> 2Al2O3

1.58 mols O atoms = 1.58/2 = 0.79 mols O2 molecules.
Use the coefficients to change from 0.79 mols O2 to mols Al.
That's 0.79 x (4 mols Al/3 mols O2) = 0.79 x 4/3 = ?