A bicyclist travels in a circle of radius 35.0 m at a constant speed of 7.00 m/s. The bicycle-rider mass is 72.0 kg.
Calculate the magnitude of the force of friction on the bicycle from the road.
Calculate the magnitude of the net force on the bicycle from the road.
An elevator weighing 2.00 x 105 N is supported by a steel cable. A free-body diagram of the elevator is shown below. What is the tension in the cable when the elevator is accelerated upward at a rate of 3.00 m/s2?
To calculate the magnitude of the force of friction on the bicycle from the road, we need to consider the centripetal force acting on the bicycle. The centripetal force is the force that keeps an object moving in a circular path.
The centripetal force can be calculated using the following formula:
F = (m * v^2) / r
Where:
F is the centripetal force,
m is the mass of the bicycle-rider (in this case, 72.0 kg),
v is the speed of the bicycle (7.00 m/s), and
r is the radius of the circular path (35.0 m).
Plugging in these values into the formula, we get:
F = (72.0 kg * (7.00 m/s)^2) / 35.0 m
Calculating this, we find:
F = (72.0 kg * 49.0 m^2/s^2) / 35.0 m
F = 100.8 N
Therefore, the magnitude of the force of friction on the bicycle from the road is 100.8 N.
Now, to calculate the magnitude of the net force on the bicycle from the road, we need to consider the force of gravity acting downward and the force of friction acting upward. Since the bicycle is traveling in a circular path at a constant speed, the net force must be zero.
Therefore, the magnitude of the net force on the bicycle from the road is 0 N.