If 32.9mL of 0.170M BaCl2 are needed to react completely with 35.0mL of 0.160M Na2SO4 . How many grams of BaSO4 will be formed?

This is a limiting reagent (LR) problem since amounts are given for BOTH reactants.

BaCl2 + Na2SO4 ==> BaSO4 + 2NaCl
mols BaCl2 = M x L = ?
mols Na2SO4 = M x L = ?
Since this is a 1:1 reaction, the LR is the one with the smaller mols.
That many mols BaSO4 will be formed.
Convert mols product to grams by g = mols x molar mass.

To find the mass of BaSO4 formed, we need to calculate the number of moles of BaCl2 and Na2SO4 that react with each other in the balanced chemical equation, and then use stoichiometry to convert the moles of BaSO4 formed.

Let's start with the balanced chemical equation for the reaction between BaCl2 and Na2SO4:

BaCl2 + Na2SO4 → BaSO4 + 2NaCl

From the equation, we can see that 1 mole of BaCl2 reacts with 1 mole of Na2SO4 to produce 1 mole of BaSO4.

Step 1: Calculate the moles of BaCl2 and Na2SO4 used in the reaction.

First, we need to convert the given volumes of BaCl2 and Na2SO4 to moles by using the formula:

moles = concentration (M) x volume (L)

For BaCl2:
moles of BaCl2 = 0.170 M x 0.0329 L = 0.005563 moles

For Na2SO4:
moles of Na2SO4 = 0.160 M x 0.0350 L = 0.005600 moles

Step 2: Determine the limiting reactant.

The limiting reactant is the reactant that is completely consumed and determines the maximum amount of product formed. To find the limiting reactant, we compare the moles of BaCl2 and Na2SO4.

Since there are fewer moles of BaCl2 (0.005563 moles) compared to Na2SO4 (0.005600 moles), BaCl2 is the limiting reactant.

Step 3: Calculate the moles of BaSO4 formed.

Since the balanced equation shows that 1 mole of BaCl2 produces 1 mole of BaSO4, the moles of BaSO4 formed will be equal to the moles of the limiting reactant.

moles of BaSO4 formed = 0.005563 moles

Step 4: Convert moles of BaSO4 to grams.

To convert moles of BaSO4 to grams, we need to use the molar mass of BaSO4, which can be found by summing up the atomic masses of its constituent elements.

The molar mass of BaSO4 = (barium: 1 x atomic mass) + (sulfur: 1 x atomic mass) + (oxygen: 4 x atomic mass)

Atomic masses: Ba = 137.33 g/mol, S = 32.07 g/mol, O = 16.00 g/mol

molar mass of BaSO4 = 137.33 + 32.07 + (4 x 16.00) = 233.38 g/mol

Now, we can calculate the mass of BaSO4 formed:

mass of BaSO4 = moles of BaSO4 formed x molar mass of BaSO4
= 0.005563 moles x 233.38 g/mol
= 1.297 g

Therefore, approximately 1.297 grams of BaSO4 will be formed.