Calculate the number of moles volume number of molecules of carbon dioxide liberated when 200 grams of limestone decomposed .
Assuming the reaction is
Ca(HCO3)2 = CACO3 + CO2 + H2O
then 200g of limestone is 200/162.11 = 1.234 moles
So, you have that many moles of CO2
1 mole occupies 22.4L at STP, and contains 6.023x10^23 molecules.
So, I guess you can now answer the questions, eh?
Limestone is composed mostly of calcite and aragonite which are two different crystal structures of CaCO3. Ca(HCO3)2 is soluble whereas CaCO3 is not.
To calculate the number of moles, volume, and number of molecules of carbon dioxide liberated when 200 grams of limestone decomposes, we need to follow a step-by-step process.
1. Determine the molar mass of limestone:
- Limestone is primarily composed of calcium carbonate (CaCO₃).
- The molar mass of calcium (Ca) is approximately 40.08 g/mol.
- The molar mass of carbon (C) is approximately 12.01 g/mol.
- The molar mass of oxygen (O) is approximately 16.00 g/mol.
- Calculate the molar mass of calcium carbonate:
Molar Mass of CaCO₃ = (Molar Mass of Ca) + (Molar Mass of C) + 3 x (Molar Mass of O)
= (40.08 g/mol) + (12.01 g/mol) + 3 x (16.00 g/mol)
= 40.08 g/mol + 12.01 g/mol + 48.00 g/mol
= 100.09 g/mol
2. Calculate the number of moles of limestone:
- Use the formula: Moles = Mass / Molar Mass
- Moles of limestone = 200 g / 100.09 g/mol
= 1.999 moles (approximately 2 moles)
3. Determine the balanced chemical equation for the decomposition of limestone:
CaCO₃(s) -> CaO(s) + CO₂(g)
4. Use the stoichiometry of the balanced equation to determine the number of moles of carbon dioxide liberated:
- From the balanced equation, we can see that 1 mole of calcium carbonate produces 1 mole of carbon dioxide.
- Since we have 2 moles of limestone, we'll also have 2 moles of carbon dioxide produced.
5. Calculate the volume of carbon dioxide:
- To calculate the volume, we need to know the temperature and pressure at which the reaction occurs.
- Assuming standard temperature and pressure, which are 0 degrees Celsius (273.15 K) and 1 atmosphere, respectively, the volume of 1 mole of any ideal gas is 22.4 L.
- Therefore, 2 moles of carbon dioxide will occupy 2 x 22.4 L = 44.8 L.
6. Calculate the number of molecules of carbon dioxide:
- Avogadro's number tells us that there are 6.022 x 10^23 molecules in 1 mole of any substance.
- Therefore, 2 moles of carbon dioxide will contain 2 x (6.022 x 10^23) molecules = 1.2044 x 10^24 molecules.
So, when 200 grams of limestone decompose, it produces approximately 2 moles of carbon dioxide, which occupy 44.8 liters of volume and contain approximately 1.2044 x 10^24 molecules.