(¡Ì3+¡Ì2) (3-¡Ì2)

Assuming you meant

(√3+√2)/(3-√2)

multiply top and bottom by 3+√2 and you have

(√3+√2)(3+√2)/7
= (3√3+√6+3√2+2)/7

I suspect a typo. Maybe you can repost with standard characters.