A sample of O2 gas occupies 1.93L at a pressure of 10.0atm at 100 degree celsius. What volume will the sample occupy at stp?
PV=kT
That is, PV/T is constant.
(10)(1.93)/(273+100) = 1V/273
so just solve for V.
To find the volume a gas sample will occupy at STP (Standard Temperature and Pressure), we need to use the ideal gas law equation:
PV = nRT
Where:
P = Pressure (in atm)
V = Volume (in liters)
n = Number of moles of gas
R = Ideal gas constant (0.0821 L·atm/(mol·K))
T = Temperature (in Kelvin)
First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:
T = 100°C + 273.15 = 373.15 K
Next, we can rearrange the ideal gas law equation to solve for the volume at STP. At STP, the temperature is 273.15 K and the pressure is 1 atm:
V₁ / P₁ = V₂ / P₂
V₂ = (V₁ * P₂) / P₁
V₂ = (1.93 L * 1 atm) / 10.0 atm
V₂ = 0.193 L
Therefore, the volume of the sample at STP will be 0.193 liters.