Use 22/7 as an approximation for p.0.7 m5.A walkway is formed by four semicircles as shown below. The diameter of the inner semicircles is 14 feet. The width between the outer and inner semicircles is 2 feet. Find the area of the walkway. Use 3.14 as an approximation for π.
can't see the diagram, but the area of a semi-circle is π/2 r^2
So, the area between two semi-circles of radii r and R is
π/2 (R^2-r^2)
You have circles of radii 14 and 16. So, plug in your numbers.
To find the area of the walkway, we need to calculate the total area covered by the four semicircles.
First, let's find the radius of the inner semicircles. The diameter is given as 14 feet, so the radius (r) is half of the diameter, which is 14/2 = 7 feet.
Next, let's find the radius of the outer semicircles. The width between the outer and inner semicircles is given as 2 feet, so the radius is the sum of the radius of the inner semicircles (7 feet) and the width (2 feet), which is 7 + 2 = 9 feet.
Now, let's calculate the area of each semicircle. The formula for the area of a semicircle is (π * r^2) / 2.
For the inner semicircles:
Area of each inner semicircle = (3.14 * 7^2) / 2
= (3.14 * 49) / 2
= 153.86 square feet
For the outer semicircles:
Area of each outer semicircle = (3.14 * 9^2) / 2
= (3.14 * 81) / 2
= 127.53 square feet
Since we have four semicircles, we can calculate the total area of the walkway by adding up the areas of all the semicircles:
Total area of the walkway = 4 * (Area of inner semicircles + Area of outer semicircles)
= 4 * (153.86 + 127.53)
= 4 * 281.39
= 1125.56 square feet
Therefore, the area of the walkway is approximately 1125.56 square feet.