How much larger than the sum of -1, -2, and 5 is the sum of the squares of these same integers?
A. 18
B. 20
C. 22
D. 28
E. 32
"larger than" means you subtract, to find the difference. So, you have
((-1)^2 + (-2)^2 + 5^2) - (-1-2+5)
1 + 4 + 25 - 2 = 28
To solve this problem, we need to find the sum of the squares of -1, -2, and 5, and then compare it to the sum of -1, -2, and 5.
First, let's find the sum of the squares of these integers:
(-1)^2 + (-2)^2 + 5^2 = 1 + 4 + 25 = 30
Next, let's find the sum of -1, -2, and 5:
-1 + (-2) + 5 = 2
Now, we need to find how much larger the sum of the squares is compared to the sum of these integers:
30 - 2 = 28
Therefore, the answer is 28, which corresponds to option D.