given the data 21, 13,13,37,13,23,25,15 what is the out liner
a.13
b.15
c.23
d.37
I think you mean outlier.
http://www.mathsisfun.com/data/outliers.html
I'll be glad to check your answer.
Oh I think I get it now
To find the outlier in a set of data, you can follow these steps:
1. Arrange the data in ascending order: 13, 13, 13, 15, 21, 23, 25, 37.
2. Calculate the lower quartile (Q1) and upper quartile (Q3) using the following formulas:
Q1 = (n+1)/4
Q3 = 3*(n+1)/4
where n is the number of data points. In this case, n = 8, so Q1 = (8+1)/4 = 2.25 and Q3 = 3*(8+1)/4 = 6.75.
3. Calculate the interquartile range (IQR) as the difference between Q3 and Q1: IQR = Q3 - Q1 = 6.75 - 2.25 = 4.5.
4. Determine the lower and upper limits for outliers using the following formulas:
Lower Limit = Q1 - 1.5 * IQR
Upper Limit = Q3 + 1.5 * IQR
In this case, Lower Limit = 2.25 - 1.5 * 4.5 = -4.5 and Upper Limit = 6.75 + 1.5 * 4.5 = 13.5.
5. Identify any data points that fall below the lower limit or above the upper limit as outliers. In this case, the only data point that falls above the upper limit is 37.
Therefore, the outlier in the data set {21, 13, 13, 37, 13, 23, 25, 15} is 37. Hence, the answer is d. 37