Two paper strips each 5 cm wide are laid across each other at an angle of 30 degrees. Determine the area of the overlapping area.

I have no idea where to start with this question or how to go on. I know it has to do with cosine or sine law. But what do I do

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  1. take two identical rulers and lay them across each other at 30° to get a mental image of the problem.

    Is the overlapping area not a rhombus with acute angles of 30° and obtuse angles of 150° ?

    So make that sketch, all 4 sides are equal, label them x

    draw a vertical from the obtuse angle to the base, you now have a 30-60-90° triangle where the side opposite the 30° is 5 cm
    You should know that the ratio of sides of the 30-60-90 is 1:√3:2
    x/√3 = 5/1
    x = 5√3

    and the area would be base x height
    = (5√3)(5) = 25√3

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