Triangles ABC and DEF are similar. If ∠ABC = 121°and ∠BCA = 35°, find the measure of angle FDE.
angle A = 180-121-35 = 24°
since angle FDE corresponds with angle CAB
angle D = 35°
Hmm. Looks to me like ∠D corresponds to ∠A = 24°
Steve is right, pardon the senior moment, and my diagram even has D corresponding with A
180-121-35=24 degrees
To find the measure of angle FDE, we can use the property of similar triangles that states corresponding angles of similar triangles are equal.
Given that triangles ABC and DEF are similar, we can conclude that:
∠ABC = ∠DEF (corresponding angles)
∠BCA = ∠EFD (corresponding angles)
From the given information, we have:
∠ABC = 121°
∠BCA = 35°
Using the property of corresponding angles, we can determine the measure of angle FDE:
∠ABC = ∠DEF (corresponding angles)
121° = ∠DEF
Therefore, the measure of angle FDE (or ∠DEF) is 121°.