how many different ways can 8 people be seated in 3 chairs
1+2=336
the first chair can be filled in 8 ways,
for each of those the 2nd chair can be filled in 7 ways, (one is seated)
and for each of those, the 3rd chair can be filled in 6 ways, so
number of ways = 8*7*6 = 336 ways
To determine the number of different ways eight people can be seated in three chairs, we can use the concept of permutations.
To explain permutations, we need to understand the factorial function. The factorial of a number n, denoted as n!, is the product of all positive integers from 1 up to n. For example, 5! = 5 x 4 x 3 x 2 x 1 = 120.
In this scenario, we have eight people and three chairs. The first chair can be occupied by any of the eight people, the second chair by any of the remaining seven people, and the third chair by any of the remaining six people. Therefore, the total number of permutations is calculated as:
8 x 7 x 6 = 336
Therefore, there are 336 different ways in which the eight people can be seated in three chairs.
Use a permutation.
8! divided by (8-3)! = 336