Can someone please help me with the following:
-(2x + 3)(3x -2)
Is it:
-6x^2 + 2x + 9x -6
-6x^2 + 11x -6
Or do I have my signs mixed up?
Thank you very much.
You do have some signs mixed up, all right...
(2x+3)(3x-2) = 6x^2+5x-6
so,
-(2x+3)(3x-2) = -(6x^2+5x-6) = -6x^2-5x+6
21
To multiply the two binomials, you can use the distributive property. The distributive property states that for any real numbers a, b, and c, a(b + c) = ab + ac.
In this case, you have -(2x + 3)(3x - 2). To simplify this expression, you can multiply each term in the first binomial by each term in the second binomial.
First, multiply -2x by each term in the second binomial:
-2x * 3x = -6x^2
-2x * -2 = +4x
Second, multiply 3 by each term in the second binomial:
3 * 3x = 9x
3 * -2 = -6
Now, add all the obtained terms together:
-6x^2 + 4x + 9x - 6
Combining like terms, you get:
-6x^2 + 13x - 6
So, the correct expansion of -(2x + 3)(3x - 2) is -6x^2 + 13x - 6.
Therefore, your second option, -6x^2 + 11x - 6, would be incorrect.