A jar contains 14 nickels, 10 dimes, 6 quarters, and 22 pennies. A coin is chosen at random from the jar. What is the probability that the coin chosen is a dime?
Option A: 5/21
Option B: 1/21
Option C: 5/26
Option D: 1/26
I'll be glad to check your answer.
A? how do I go about figuring this out?
Start with this fraction >> 10/52
(10 dimes out of 52 coins)
Now reduce or simplify 10/52.
Obviously, Option A is not right.
C. 5/26
Right.
To find the probability of choosing a dime, we need to determine the total number of coins in the jar first.
The total number of coins in the jar is calculated by adding the number of nickels, dimes, quarters, and pennies together:
Total number of coins = 14 (nickels) + 10 (dimes) + 6 (quarters) + 22 (pennies) = 52 (coins)
Next, we can calculate the probability of choosing a dime by dividing the number of dimes by the total number of coins in the jar:
Probability of choosing a dime = Number of dimes / Total number of coins
Probability of choosing a dime = 10 (dimes) / 52 (coins)
Simplifying the fraction, we get:
Probability of choosing a dime = 5/26
Therefore, the correct answer is Option C: 5/26.