A gas expands from a volume of 2.00m^3 to 6.00m^3 and does 6912 joules of work against a constant outside pressure. Calculate this outside pressure in Pa.

The answer is 1730 Pa, but I don't know how to get that.

I honestly have no idea where to start or what formulas to use. Please help me.

Work= P*change in volume.

Solve for pressure.

thank you very much

To solve this problem, you can use the formula for work done by a gas, which is:

Work = Pressure * Change in Volume

In this case, the change in volume is ΔV = 6.00 m^3 - 2.00 m^3 = 4.00 m^3. The work done is given as 6912 J.

Now, rearrange the formula to solve for pressure:

Pressure = Work / Change in Volume

Substitute the given values into the formula:

Pressure = 6912 J / 4.00 m^3

To convert the volume from m^3 to cm^3, multiply by 100^3:

Pressure = 6912 J / (4.00 m^3) * (100 cm / 1 m)^3

Pressure = 6912 J / (4.00 * 100^3 cm^3)

Simplify the expression:

Pressure = 6912 J / (4.00 * 100^3 cm^3)

Pressure = 6912 J / 4,000,000 cm^3

Pressure = 1.728 Pa

Therefore, the outside pressure is approximately 1730 Pa.