A gas expands from a volume of 2.00m^3 to 6.00m^3 and does 6912 joules of work against a constant outside pressure. Calculate this outside pressure in Pa.
The answer is 1730 Pa, but I don't know how to get that.
I honestly have no idea where to start or what formulas to use. Please help me.
Work= P*change in volume.
Solve for pressure.
thank you very much
To solve this problem, you can use the formula for work done by a gas, which is:
Work = Pressure * Change in Volume
In this case, the change in volume is ΔV = 6.00 m^3 - 2.00 m^3 = 4.00 m^3. The work done is given as 6912 J.
Now, rearrange the formula to solve for pressure:
Pressure = Work / Change in Volume
Substitute the given values into the formula:
Pressure = 6912 J / 4.00 m^3
To convert the volume from m^3 to cm^3, multiply by 100^3:
Pressure = 6912 J / (4.00 m^3) * (100 cm / 1 m)^3
Pressure = 6912 J / (4.00 * 100^3 cm^3)
Simplify the expression:
Pressure = 6912 J / (4.00 * 100^3 cm^3)
Pressure = 6912 J / 4,000,000 cm^3
Pressure = 1.728 Pa
Therefore, the outside pressure is approximately 1730 Pa.