If the relative density of a metal is 19 what will be the mass of 20cm^3 of the metal when immersed in water.
bouyancy will be 20grams (mass water displaced)
the apparent mass=relative mass*volume-bouyancy
apparent mass=18*20 grams.
Now caution, your teacher might be trying to trick you, the real mass of the metal is constant, regardless if it is immersed or not.
Please solve it
To find the mass of the metal when immersed in water, we need to use the concept of relative density and the density of water.
Relative density is defined as the ratio of the density of a substance compared to the density of another substance, usually a reference substance. In this case, we need to find the density of the metal, given that its relative density is 19.
First, let's find the density of the reference substance, which is water. The density of water is approximately 1 g/cm^3.
Next, we can use the formula for relative density:
Relative Density = Density of the Metal / Density of Water
By rearranging the formula, we can find the density of the metal:
Density of the Metal = Relative Density * Density of Water
Plugging in the values, we have:
Density of the Metal = 19 * 1 g/cm^3
Density of the Metal = 19 g/cm^3
Now that we have the density of the metal, we can calculate the mass of 20 cm^3 of the metal when immersed in water. The formula to find the mass is:
Mass = Density × Volume
Plugging in the values, we get:
Mass = 19 g/cm^3 × 20 cm^3
Mass = 380 g
Therefore, the mass of 20 cm^3 of the metal when immersed in water is 380 grams.